What is the value of cos(60)*20 ?

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cos(60)*20

cos (6 0^{\circ}) \cdot 20

10

Solution steps

cos (6 0^{\circ}) \cdot 20

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

cos (6 0^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{1}{2}

= \frac{1}{2} \cdot 20

Simplify

\frac{1}{2} \cdot 20 : 10

\frac{1}{2} \cdot 20

Convert element to fraction:

20 = \frac{20}{1}

= \frac{1}{2} \cdot \frac{20}{1}

Cross-cancel common factor:

2

= \frac{10}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 10

= 10

arccos (\frac{6}{4})

cos (\frac{4}{π})

36 cos (2 8^{\circ})

cot (\frac{100 π}{101})

\frac{1 - cos ( - 0.01 )}{sin ( - 0.01 )}