What is the value of cos(arctan(4/3)-arcsin(3/5)) ?

The value of cos(arctan(4/3)-arcsin(3/5)) is 24/25

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cos(arctan(4/3)-arcsin(3/5))

Solution

cos (arctan (\frac{4}{3}) - arcsin (\frac{3}{5}))

Solution

\frac{24}{25}

Decimal Notation

0.96

Solution steps

cos (arctan (\frac{4}{3}) - arcsin (\frac{3}{5}))

Rewrite using trig identities:

cos (arctan (\frac{4}{3})) cos (arcsin (\frac{3}{5})) + sin (arctan (\frac{4}{3})) sin (arcsin (\frac{3}{5}))

cos (arctan (\frac{4}{3}) - arcsin (\frac{3}{5}))

Use the Angle Difference identity:

cos (s - t) = cos (s) cos (t) + sin (s) sin (t)

= cos (arctan (\frac{4}{3})) cos (arcsin (\frac{3}{5})) + sin (arctan (\frac{4}{3})) sin (arcsin (\frac{3}{5}))

= cos (arctan (\frac{4}{3})) cos (arcsin (\frac{3}{5})) + sin (arctan (\frac{4}{3})) sin (arcsin (\frac{3}{5}))

Rewrite using trig identities:

cos (arctan (\frac{4}{3})) = \frac{3}{5}

cos (arctan (\frac{4}{3}))

Rewrite using trig identities:

cos (arctan (\frac{4}{3})) = \frac{1 + ( \frac{4}{3} ) ^{2}}{1 + ( \frac{4}{3} ) ^{2}}

Use the following identity:

cos (arctan (x)) = \frac{1 + x ^{2}}{1 + x ^{2}}

= \frac{1 + ( \frac{4}{3} ) ^{2}}{1 + ( \frac{4}{3} ) ^{2}}

= \frac{1 + ( \frac{4}{3} ) ^{2}}{1 + ( \frac{4}{3} ) ^{2}}

Simplify

= \frac{3}{5}

Rewrite using trig identities:

cos (arcsin (\frac{3}{5})) = \frac{4}{5}

cos (arcsin (\frac{3}{5}))

Rewrite using trig identities:

cos (arcsin (\frac{3}{5})) = 1 - (\frac{3}{5})^{2}

Use the following identity:

cos (arcsin (x)) = 1 - x^{2}

= 1 - (\frac{3}{5})^{2}

= 1 - (\frac{3}{5})^{2}

Simplify

= \frac{4}{5}

Rewrite using trig identities:

sin (arctan (\frac{4}{3})) = \frac{4}{5}

sin (arctan (\frac{4}{3}))

Rewrite using trig identities:

sin (arctan (\frac{4}{3})) = \frac{( \frac{4}{3} ) 1 + ( \frac{4}{3} ) ^{2}}{1 + ( \frac{4}{3} ) ^{2}}

Use the following identity:

sin (arctan (x)) = \frac{x 1 + x ^{2}}{1 + x ^{2}}

= \frac{( \frac{4}{3} ) 1 + ( \frac{4}{3} ) ^{2}}{1 + ( \frac{4}{3} ) ^{2}}

= \frac{\frac{4}{3} 1 + ( \frac{4}{3} ) ^{2}}{1 + ( \frac{4}{3} ) ^{2}}

Simplify

= \frac{4}{5}

Rewrite using trig identities:

sin (arcsin (\frac{3}{5})) = \frac{3}{5}

Use the following identity:

sin (arcsin (x)) = x

= \frac{3}{5}

= \frac{3}{5} \cdot \frac{4}{5} + \frac{4}{5} \cdot \frac{3}{5}

Simplify

\frac{3}{5} \cdot \frac{4}{5} + \frac{4}{5} \cdot \frac{3}{5} : \frac{24}{25}

\frac{3}{5} \cdot \frac{4}{5} + \frac{4}{5} \cdot \frac{3}{5}

Add similar elements:

\frac{3}{5} \cdot \frac{4}{5} + \frac{4}{5} \cdot \frac{3}{5} = 2 \cdot \frac{3}{5} \cdot \frac{4}{5}

= 2 \cdot \frac{3}{5} \cdot \frac{4}{5}

Convert element to fraction:

2 = \frac{2}{1}

= \frac{2}{1} \cdot \frac{3}{5} \cdot \frac{4}{5}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{2 \cdot 3 \cdot 4}{1 \cdot 5 \cdot 5}

Multiply the numbers:

2 \cdot 3 \cdot 4 = 24

= \frac{24}{1 \cdot 5 \cdot 5}

Multiply the numbers:

1 \cdot 5 \cdot 5 = 25

= \frac{24}{25}

= \frac{24}{25}

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Frequently Asked Questions (FAQ)

What is the value of cos(arctan(4/3)-arcsin(3/5)) ?
The value of cos(arctan(4/3)-arcsin(3/5)) is 24/25