What is the value of tanh(0.5) ?

The value of tanh(0.5) is (e^2-2e^{1/2}sqrt(e)+1)/(e^2-1)

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tanh(0.5)

Solution

tanh (0.5)

Solution

\frac{e ^{2} - 2 e ^{\frac{1}{2}} e + 1}{e ^{2} - 1}

Decimal Notation

0.46211 \dots

Solution steps

tanh (0.5)

= tanh (\frac{1}{2})

Rewrite using trig identities:

\frac{e ^{2} - 2 e ^{\frac{1}{2}} e + 1}{e ^{2} - 1}

tanh (\frac{1}{2})

Use the Hyperbolic identity:

tanh (x) = \frac{e ^{x} - e ^{- x}}{e ^{x} + e ^{- x}}

= \frac{e ^{\frac{1}{2}} - e ^{- \frac{1}{2}}}{e ^{\frac{1}{2}} + e ^{- \frac{1}{2}}}

\frac{e ^{\frac{1}{2}} - e ^{- \frac{1}{2}}}{e ^{\frac{1}{2}} + e ^{- \frac{1}{2}}} = \frac{e ^{2} - 2 e ^{\frac{1}{2}} e + 1}{e ^{2} - 1}

\frac{e ^{\frac{1}{2}} - e ^{- \frac{1}{2}}}{e ^{\frac{1}{2}} + e ^{- \frac{1}{2}}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

e^{- \frac{1}{2}} = \frac{1}{e}

= \frac{e ^{\frac{1}{2}} - \frac{1}{e}}{e ^{\frac{1}{2}} + \frac{1}{e}}

Join

e^{\frac{1}{2}} + \frac{1}{e} : \frac{e ^{\frac{1}{2}} e + 1}{e}

e^{\frac{1}{2}} + \frac{1}{e}

Convert element to fraction:

e^{\frac{1}{2}} = \frac{e ^{\frac{1}{2}} e}{e}

= \frac{e ^{\frac{1}{2}} e}{e} + \frac{1}{e}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{e ^{\frac{1}{2}} e + 1}{e}

= \frac{e ^{\frac{1}{2}} - \frac{1}{e}}{\frac{e ^{\frac{1}{2}} e + 1}{e}}

Join

e^{\frac{1}{2}} - \frac{1}{e} : \frac{e ^{\frac{1}{2}} e - 1}{e}

e^{\frac{1}{2}} - \frac{1}{e}

Convert element to fraction:

e^{\frac{1}{2}} = \frac{e ^{\frac{1}{2}} e}{e}

= \frac{e ^{\frac{1}{2}} e}{e} - \frac{1}{e}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{e ^{\frac{1}{2}} e - 1}{e}

= \frac{\frac{e ^{\frac{1}{2}} e - 1}{e}}{\frac{e ^{\frac{1}{2}} e + 1}{e}}

Divide fractions:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( e ^{\frac{1}{2}} e - 1 ) e}{e ( e ^{\frac{1}{2}} e + 1 )}

Cancel the common factor:

e

= \frac{e ^{\frac{1}{2}} e - 1}{e ^{\frac{1}{2}} e + 1}

Rationalize

\frac{e ^{\frac{1}{2}} e - 1}{e ^{\frac{1}{2}} e + 1} : \frac{e ^{2} - 2 e ^{\frac{1}{2}} e + 1}{e ^{2} - 1}

\frac{e ^{\frac{1}{2}} e - 1}{e ^{\frac{1}{2}} e + 1}

Multiply by the conjugate

\frac{e ^{\frac{1}{2}} e - 1}{e ^{\frac{1}{2}} e - 1}

= \frac{( e ^{\frac{1}{2}} e - 1 ) ( e ^{\frac{1}{2}} e - 1 )}{( e ^{\frac{1}{2}} e + 1 ) ( e ^{\frac{1}{2}} e - 1 )}

(e^{\frac{1}{2}} e - 1) (e^{\frac{1}{2}} e - 1) = e^{2} - 2 e^{\frac{1}{2}} e + 1

(e^{\frac{1}{2}} e - 1) (e^{\frac{1}{2}} e - 1)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(e^{\frac{1}{2}} e - 1) (e^{\frac{1}{2}} e - 1) = (e^{\frac{1}{2}} e - 1)^{1 + 1}

= (e^{\frac{1}{2}} e - 1)^{1 + 1}

Add the numbers:

1 + 1 = 2

= (e^{\frac{1}{2}} e - 1)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = e^{\frac{1}{2}} e, b = 1

= (e^{\frac{1}{2}} e)^{2} - 2 e^{\frac{1}{2}} e \cdot 1 + 1^{2}

Simplify

(e^{\frac{1}{2}} e)^{2} - 2 e^{\frac{1}{2}} e \cdot 1 + 1^{2} : e^{2} - 2 e^{\frac{1}{2}} e + 1

(e^{\frac{1}{2}} e)^{2} - 2 e^{\frac{1}{2}} e \cdot 1 + 1^{2}

Apply rule

1^{a} = 1

1^{2} = 1

= (e^{\frac{1}{2}} e)^{2} - 2 \cdot 1 \cdot e^{\frac{1}{2}} e + 1

(e^{\frac{1}{2}} e)^{2} = e^{2}

(e^{\frac{1}{2}} e)^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (e)^{2} (e^{\frac{1}{2}})^{2}

(e^{\frac{1}{2}})^{2} : e

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= e^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= e

= e (e)^{2}

(e)^{2} : e

Apply radical rule:

a = a^{\frac{1}{2}}

= (e^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= e^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= e

= ee

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ee = e^{1 + 1}

= e^{1 + 1}

Add the numbers:

1 + 1 = 2

= e^{2}

2 e^{\frac{1}{2}} e \cdot 1 = 2 e^{\frac{1}{2}} e

2 e^{\frac{1}{2}} e \cdot 1

Multiply the numbers:

2 \cdot 1 = 2

= 2 e^{\frac{1}{2}} e

= e^{2} - 2 e^{\frac{1}{2}} e + 1

= e^{2} - 2 e^{\frac{1}{2}} e + 1

(e^{\frac{1}{2}} e + 1) (e^{\frac{1}{2}} e - 1) = e^{2} - 1

(e^{\frac{1}{2}} e + 1) (e^{\frac{1}{2}} e - 1)

e^{\frac{1}{2}} e = e

e^{\frac{1}{2}} e

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{\frac{1}{2}} e = e^{\frac{1}{2}} e^{\frac{1}{2}} = e^{\frac{1}{2} + \frac{1}{2}}

= e^{\frac{1}{2} + \frac{1}{2}}

Add similar elements:

\frac{1}{2} + \frac{1}{2} = 2 \cdot \frac{1}{2}

= e^{2 \cdot \frac{1}{2}}

Multiply

2 \cdot \frac{1}{2} : 1

2 \cdot \frac{1}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= e^{1}

Apply rule

a^{1} = a

= e

= (e + 1) (e^{\frac{1}{2}} e - 1)

e^{\frac{1}{2}} e = e

e^{\frac{1}{2}} e

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{\frac{1}{2}} e = e^{\frac{1}{2}} e^{\frac{1}{2}} = e^{\frac{1}{2} + \frac{1}{2}}

= e^{\frac{1}{2} + \frac{1}{2}}

Add similar elements:

\frac{1}{2} + \frac{1}{2} = 2 \cdot \frac{1}{2}

= e^{2 \cdot \frac{1}{2}}

Multiply

2 \cdot \frac{1}{2} : 1

2 \cdot \frac{1}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= e^{1}

Apply rule

a^{1} = a

= e

= (e + 1) (e - 1)

Apply Difference of Two Squares Formula:

(a + b) (a - b) = a^{2} - b^{2}

a = e, b = 1

= e^{2} - 1^{2}

Apply rule

1^{a} = 1

1^{2} = 1

= e^{2} - 1

= \frac{e ^{2} - 2 e ^{\frac{1}{2}} e + 1}{e ^{2} - 1}

= \frac{e ^{2} - 2 e ^{\frac{1}{2}} e + 1}{e ^{2} - 1}

= \frac{e ^{2} - 2 e ^{\frac{1}{2}} e + 1}{e ^{2} - 1}

= \frac{e ^{2} - 2 e ^{\frac{1}{2}} e + 1}{e ^{2} - 1}

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Frequently Asked Questions (FAQ)

What is the value of tanh(0.5) ?
The value of tanh(0.5) is (e^2-2e^{1/2}sqrt(e)+1)/(e^2-1)