What is the general solution for 6sin(3x)+1=7 ?

The general solution for 6sin(3x)+1=7 is x= pi/6+(2pin)/3

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6sin(3x)+1=7

6 sin (3 x) + 1 = 7

x = \frac{π}{6} + \frac{2 πn}{3}

Solution steps

6 sin (3 x) + 1 = 7

Move

1

to the right side

6 sin (3 x) = 6

Divide both sides by

6

sin (3 x) = 1

General solutions for

sin (3 x) = 1

3 x = \frac{π}{2} + 2 πn

Solve

3 x = \frac{π}{2} + 2 πn : x = \frac{π}{6} + \frac{2 πn}{3}

x = \frac{π}{6} + \frac{2 πn}{3}

sin (\frac{π}{12})

arccos (\frac{2}{2})

cos (\frac{π}{6})

sin (1 0^{\circ})

cos (x) cos (3 x) + sin (x) sin (3 x) = 0, 0 \leq x \leq 2 π

What is the general solution for 6sin(3x)+1=7 ?
The general solution for 6sin(3x)+1=7 is x= pi/6+(2pin)/3