What is the value of -arcsin(-1) ?

The value of -arcsin(-1) is pi/2

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-arcsin(-1)

- arcsin (- 1)

\frac{π}{2}

Decimal Notation

90

Solution steps

- arcsin (- 1)

Rewrite using trig identities:

arcsin (- 1) = - \frac{π}{2}

arcsin (- 1)

Use the following property:

arcsin (- x) = - arcsin (x)

arcsin (- 1) = - arcsin (1)

= - arcsin (1)

Use the following trivial identity:

arcsin (1) = \frac{π}{2}

arcsin (1)

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= \frac{π}{2}

= - \frac{π}{2}

= - (- \frac{π}{2})

Simplify

= \frac{π}{2}

arctan (- \frac{3}{8})

sin (arcsin (\frac{7}{25}) + arccos (- \frac{5}{13}))

\frac{12 sin ( 2 8 ^{\circ} )}{sin ( 10 4 ^{\circ} )}

2 \cdot tan (3 0^{\circ})

6 cos (9 0^{\circ})