{
"query": {
"display": "$$\\sin^{2}\\left(\\frac{17π}{2}\\right)+\\cos^{2}\\left(\\frac{17π}{2}\\right)$$",
"symbolab_question": "TRIG_EVALUATE#\\sin^{2}(\\frac{17π}{2})+\\cos^{2}(\\frac{17π}{2})"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Evaluate Functions",
"subTopic": "Simplified",
"default": "1",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\sin^{2}\\left(\\frac{17π}{2}\\right)+\\cos^{2}\\left(\\frac{17π}{2}\\right)=1$$",
"input": "\\sin^{2}\\left(\\frac{17π}{2}\\right)+\\cos^{2}\\left(\\frac{17π}{2}\\right)",
"steps": [
{
"type": "interim",
"title": "$$\\sin\\left(\\frac{17π}{2}\\right)=\\sin\\left(\\frac{π}{2}\\right)$$",
"input": "\\sin\\left(\\frac{17π}{2}\\right)",
"result": "=\\sin^{2}\\left(\\frac{π}{2}\\right)+\\cos^{2}\\left(\\frac{17π}{2}\\right)",
"steps": [
{
"type": "step",
"primary": "Rewrite $$\\frac{17π}{2}$$ as $$2π\\cdot\\:4+\\frac{π}{2}$$",
"result": "=\\sin\\left(2π4+\\frac{π}{2}\\right)"
},
{
"type": "step",
"primary": "Apply the periodicity of $$\\sin$$: $$\\sin\\left(x+2π\\cdot\\:k\\right)=\\sin\\left(x\\right)$$",
"secondary": [
"$$\\sin\\left(2π\\cdot\\:4+\\frac{π}{2}\\right)=\\sin\\left(\\frac{π}{2}\\right)$$"
],
"result": "=\\sin\\left(\\frac{π}{2}\\right)"
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "interim",
"title": "$$\\cos\\left(\\frac{17π}{2}\\right)=\\cos\\left(\\frac{π}{2}\\right)$$",
"input": "\\cos\\left(\\frac{17π}{2}\\right)",
"result": "=\\sin^{2}\\left(\\frac{π}{2}\\right)+\\cos^{2}\\left(\\frac{π}{2}\\right)",
"steps": [
{
"type": "step",
"primary": "Rewrite $$\\frac{17π}{2}$$ as $$2π\\cdot\\:4+\\frac{π}{2}$$",
"result": "=\\cos\\left(2π4+\\frac{π}{2}\\right)"
},
{
"type": "step",
"primary": "Apply the periodicity of $$\\cos$$: $$\\cos\\left(x+2π\\cdot\\:k\\right)=\\cos\\left(x\\right)$$",
"secondary": [
"$$\\cos\\left(2π\\cdot\\:4+\\frac{π}{2}\\right)=\\cos\\left(\\frac{π}{2}\\right)$$"
],
"result": "=\\cos\\left(\\frac{π}{2}\\right)"
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "interim",
"title": "Use the following trivial identity:$${\\quad}\\sin\\left(\\frac{π}{2}\\right)=1$$",
"input": "\\sin\\left(\\frac{π}{2}\\right)",
"steps": [
{
"type": "step",
"primary": "$$\\sin\\left(x\\right)$$ periodicity table with $$2πn$$ cycle:<br/>$$\\begin{array}{|c|c|c|c|}\\hline x&\\sin(x)&x&\\sin(x)\\\\\\hline 0&0&π&0\\\\\\hline \\frac{π}{6}&\\frac{1}{2}&\\frac{7π}{6}&-\\frac{1}{2}\\\\\\hline \\frac{π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{5π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{π}{3}&\\frac{\\sqrt{3}}{2}&\\frac{4π}{3}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{π}{2}&1&\\frac{3π}{2}&-1\\\\\\hline \\frac{2π}{3}&\\frac{\\sqrt{3}}{2}&\\frac{5π}{3}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{3π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{7π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{5π}{6}&\\frac{1}{2}&\\frac{11π}{6}&-\\frac{1}{2}\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "=1"
}
],
"meta": {
"interimType": "Trig Trivial Angle Value Title 0Eq"
}
},
{
"type": "interim",
"title": "Use the following trivial identity:$${\\quad}\\cos\\left(\\frac{π}{2}\\right)=0$$",
"input": "\\cos\\left(\\frac{π}{2}\\right)",
"steps": [
{
"type": "step",
"primary": "$$\\cos\\left(x\\right)$$ periodicity table with $$2πn$$ cycle:<br/>$$\\begin{array}{|c|c|c|c|}\\hline x&\\cos(x)&x&\\cos(x)\\\\\\hline 0&1&π&-1\\\\\\hline \\frac{π}{6}&\\frac{\\sqrt{3}}{2}&\\frac{7π}{6}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{5π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{π}{3}&\\frac{1}{2}&\\frac{4π}{3}&-\\frac{1}{2}\\\\\\hline \\frac{π}{2}&0&\\frac{3π}{2}&0\\\\\\hline \\frac{2π}{3}&-\\frac{1}{2}&\\frac{5π}{3}&\\frac{1}{2}\\\\\\hline \\frac{3π}{4}&-\\frac{\\sqrt{2}}{2}&\\frac{7π}{4}&\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{5π}{6}&-\\frac{\\sqrt{3}}{2}&\\frac{11π}{6}&\\frac{\\sqrt{3}}{2}\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "=0"
}
],
"meta": {
"interimType": "Trig Trivial Angle Value Title 0Eq"
}
},
{
"type": "step",
"result": "=1^{2}+0^{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "=1"
}
],
"meta": {
"solvingClass": "Trig Evaluate",
"practiceLink": "/practice/trigonometry-practice#area=main&subtopic=Evaluate%20Functions",
"practiceTopic": "Evaluate Functions"
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
Solution steps
Rewrite as
Apply the periodicity of :
Rewrite as
Apply the periodicity of :
Use the following trivial identity:
periodicity table with cycle:
Use the following trivial identity:
periodicity table with cycle:
Simplify
Popular Examples
Frequently Asked Questions (FAQ)
What is the value of sin^2((17pi)/2)+cos^2((17pi)/2) ?
The value of sin^2((17pi)/2)+cos^2((17pi)/2) is 1