What is the general solution for csc(4x)-2=0 ?

The general solution for csc(4x)-2=0 is x= pi/(24)+(pin)/2 ,x=(5pi}{24}+\frac{pin)/2

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csc(4x)-2=0

csc (4 x) - 2 = 0

x = \frac{π}{24} + \frac{πn}{2}, x = \frac{5 π}{24} + \frac{πn}{2}

Solution steps

csc (4 x) - 2 = 0

Move

2

to the right side

csc (4 x) = 2

General solutions for

csc (4 x) = 2

4 x = \frac{π}{6} + 2 πn, 4 x = \frac{5 π}{6} + 2 πn

Solve

4 x = \frac{π}{6} + 2 πn : x = \frac{π}{24} + \frac{πn}{2}

Solve

4 x = \frac{5 π}{6} + 2 πn : x = \frac{5 π}{24} + \frac{πn}{2}

x = \frac{π}{24} + \frac{πn}{2}, x = \frac{5 π}{24} + \frac{πn}{2}

cos (x) = - 0.7

tan^{2} (θ) - tan (θ) = 0

cos (8 0^{\circ})

3 tan (θ) - 1 = 0

sin (x) = - \frac{3}{2}

What is the general solution for csc(4x)-2=0 ?
The general solution for csc(4x)-2=0 is x= pi/(24)+(pin)/2 ,x=(5pi}{24}+\frac{pin)/2