What is the value of sec(arccos(-3/4)) ?

The value of sec(arccos(-3/4)) is -4/3

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sec(arccos(-3/4))

sec (arccos (- \frac{3}{4}))

- \frac{4}{3}

Decimal Notation

- 1.33333 \dots

Solution steps

sec (arccos (- \frac{3}{4}))

Rewrite using trig identities:

sec (arccos (- \frac{3}{4})) = \frac{1}{( - \frac{3}{4} )}

Use the following identity:

sec (arccos (x)) = \frac{1}{x}

= \frac{1}{( - \frac{3}{4} )}

= \frac{1}{- \frac{3}{4}}

Simplify

= - \frac{4}{3}

cos (3 π) + sin (3 π)

arctan (\frac{- 6.72}{32.61})

csc (4 8^{\circ})

cos^{2} (3 4^{\circ}) - sin^{2} (3 4^{\circ})

π^{2} cos (π)