What is the value of -sin(pi/4+(3pi)/4) ?

The value of -sin(pi/4+(3pi)/4) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-sin(pi/4+(3pi)/4)

- sin (\frac{π}{4} + \frac{3 π}{4})

0

Solution steps

- sin (\frac{π}{4} + \frac{3 π}{4})

Rewrite using trig identities:

sin (\frac{π}{4} + \frac{3 π}{4}) = 0

sin (\frac{π}{4} + \frac{3 π}{4})

Simplify:

\frac{π}{4} + \frac{3 π}{4} = π

\frac{π}{4} + \frac{3 π}{4}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{π + 3 π}{4}

Add similar elements:

π + 3 π = 4 π

= \frac{4 π}{4}

Divide the numbers:

\frac{4}{4} = 1

= π

= sin (π)

Use the following trivial identity:

sin (π) = 0

sin (π)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= 0

= - 0

Simplify

= 0

sin (14. 5^{\circ})

18 sin (3 2^{\circ})

cos (arccos (- 0.5))

arctan (\frac{- 6}{4})

arctan (\frac{- 6}{6})