What is the value of sin(arccos(0)-arccos(1/2)) ?

The value of sin(arccos(0)-arccos(1/2)) is 1/2

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Popular >

sin(arccos(0)-arccos(1/2))

Solution

sin (arccos (0) - arccos (\frac{1}{2}))

Solution

\frac{1}{2}

Decimal Notation

0.5

Solution steps

sin (arccos (0) - arccos (\frac{1}{2}))

Rewrite using trig identities:

arccos (0) - arccos (\frac{1}{2}) = arccos (\frac{3}{2})

arccos (0) - arccos (\frac{1}{2})

Use the Sum to Product identity:

arccos (s) - arccos (t) = arccos (s t + (1 - s^{2}) (1 - t^{2}))

= arccos 0 \cdot \frac{1}{2} + (1 - 0^{2}) (1 - (\frac{1}{2})^{2})

Simplify:

0 \cdot \frac{1}{2} + (1 - 0^{2}) (1 - (\frac{1}{2})^{2}) = \frac{3}{2}

0 \cdot \frac{1}{2} + (1 - 0^{2}) (1 - (\frac{1}{2})^{2})

Apply rule

0^{a} = 0

0^{2} = 0

= 0 \cdot \frac{1}{2} + (1 - 0) (- (\frac{1}{2})^{2} + 1)

0 \cdot \frac{1}{2} = 0

0 \cdot \frac{1}{2}

Apply rule

0 \cdot a = 0

= 0

(1 - 0) (1 - (\frac{1}{2})^{2}) = \frac{3}{2}

(1 - 0) (1 - (\frac{1}{2})^{2})

Subtract the numbers:

1 - 0 = 1

= 1 \cdot (- (\frac{1}{2})^{2} + 1)

(\frac{1}{2})^{2} = \frac{1}{4}

(\frac{1}{2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{2 ^{2}}

Apply rule

1^{a} = 1

1^{2} = 1

= \frac{1}{2 ^{2}}

2^{2} = 4

= \frac{1}{4}

= 1 \cdot (- \frac{1}{4} + 1)

Join

1 - \frac{1}{4} : \frac{3}{4}

1 - \frac{1}{4}

Convert element to fraction:

1 = \frac{1 \cdot 4}{4}

= \frac{1 \cdot 4}{4} - \frac{1}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 4 - 1}{4}

1 \cdot 4 - 1 = 3

1 \cdot 4 - 1

Multiply the numbers:

1 \cdot 4 = 4

= 4 - 1

Subtract the numbers:

4 - 1 = 3

= 3

= \frac{3}{4}

= 1 \cdot \frac{3}{4}

Multiply:

1 \cdot \frac{3}{4} = \frac{3}{4}

= \frac{3}{4}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{3}{4}

4 = 2

4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

2^{2} = 2

= 2

= \frac{3}{2}

= 0 + \frac{3}{2}

0 + \frac{3}{2} = \frac{3}{2}

= \frac{3}{2}

= arccos (\frac{3}{2})

= sin (arccos (\frac{3}{2}))

Rewrite using trig identities:

sin (arccos (\frac{3}{2})) = 1 - (\frac{3}{2})^{2}

Use the following identity:

sin (arccos (x)) = 1 - x^{2}

= 1 - (\frac{3}{2})^{2}

= 1 - (\frac{3}{2})^{2}

Simplify

= \frac{1}{2}

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Frequently Asked Questions (FAQ)

What is the value of sin(arccos(0)-arccos(1/2)) ?
The value of sin(arccos(0)-arccos(1/2)) is 1/2