What is the value of 2(1)^2+2arcsin(1) ?

The value of 2(1)^2+2arcsin(1) is 2+pi

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2(1)^2+2arcsin(1)

2 (1)^{2} + 2 arcsin (1)

2 + π

Decimal Notation

294.59

Solution steps

2 (1)^{2} + 2 arcsin (1)

= 2 \cdot 1^{2} + 2 arcsin (1)

Use the following trivial identity:

arcsin (1) = \frac{π}{2}

arcsin (1)

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= \frac{π}{2}

= 2 \cdot 1^{2} + 2 \cdot \frac{π}{2}

Simplify

2 \cdot 1^{2} + 2 \cdot \frac{π}{2} : 2 + π

2 \cdot 1^{2} + 2 \cdot \frac{π}{2}

Apply rule

1^{a} = 1

1^{2} = 1

= 2 \cdot 1 + 2 \cdot \frac{π}{2}

2 \cdot 1 = 2

2 \cdot 1

Multiply the numbers:

2 \cdot 1 = 2

= 2

2 \cdot \frac{π}{2} = π

2 \cdot \frac{π}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 2}{2}

Cancel the common factor:

2

= π

= 2 + π

= 2 + π

sin (7 \cdot \frac{π}{2})

csc (\frac{2}{2})

sin (- 0.6)

8 cos (27 0^{\circ})

cos^{2} (3 3^{\circ})