What is the value of -pi/2+sin(-pi/2) ?

The value of -pi/2+sin(-pi/2) is -pi/2-1

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-pi/2+sin(-pi/2)

- \frac{π}{2} + sin (- \frac{π}{2})

- \frac{π}{2} - 1

Decimal Notation

- 2.57079 \dots

Solution steps

- \frac{π}{2} + sin (- \frac{π}{2})

Rewrite using trig identities:

sin (- \frac{π}{2}) = - 1

sin (- \frac{π}{2})

Use the following property:

sin (- x) = - sin (x)

sin (- \frac{π}{2}) = - sin (\frac{π}{2})

= - sin (\frac{π}{2})

Use the following trivial identity:

sin (\frac{π}{2}) = 1

sin (\frac{π}{2})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

= - 1

= - \frac{π}{2} - 1

csc (7 π)

cos (sin (0))

6^{2} + 8^{2} + 2 \cdot 6 \cdot 8 \cdot cos (9 0^{\circ})

tan (\frac{2 π}{3} + \frac{π}{4})

tan (0.24 π)

What is the value of -pi/2+sin(-pi/2) ?
The value of -pi/2+sin(-pi/2) is -pi/2-1