What is the value of 5cos(150) ?

The value of 5cos(150) is -(5sqrt(3))/2

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5cos(150)

5 cos (15 0^{\circ})

- \frac{5 3}{2}

Decimal Notation

- 4.33012 \dots

Solution steps

5 cos (15 0^{\circ})

Use the following trivial identity:

cos (15 0^{\circ}) = - \frac{3}{2}

cos (15 0^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= - \frac{3}{2}

= 5 (- \frac{3}{2})

Simplify

5 (- \frac{3}{2}) : - \frac{5 3}{2}

5 (- \frac{3}{2})

Remove parentheses:

(- a) = - a

= - 5 \cdot \frac{3}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{3 \cdot 5}{2}

= - \frac{5 3}{2}

4 cot^{3} (13 5^{\circ}) + 7 tan^{4} (15 0^{\circ}) - csc^{2} (24 0^{\circ})

cos (π (2))

arccos (\frac{3.9}{8.5})

\frac{tan ( 1 2 ^{\circ} )}{1 - tan ^{2} ( 1 2 ^{\circ} )}

sin (10 5^{\circ}) sin (1 5^{\circ})