What is the value of (sin^2(pi))/2 ?

The value of (sin^2(pi))/2 is 0

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(sin^2(pi))/2

\frac{sin ^{2} ( π )}{2}

0

Solution steps

\frac{sin ^{2} ( π )}{2}

Use the following trivial identity:

sin (π) = 0

sin (π)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= \frac{0 ^{2}}{2}

Simplify

= 0

sin (1) + cos (1 + 1^{2}) - 1

cos (\frac{7 π}{9})

\frac{\frac{π}{6} cos ( \frac{π}{6} ) - sin ( \frac{π}{6} )}{( \frac{π}{6} ) ^{2}}

2 cos (\frac{π}{2}) + sin (π)

6 cos (\frac{11 π}{6})