What is the value of arcsin(sin((17pi)/6)) ?

The value of arcsin(sin((17pi)/6)) is pi/6

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arcsin(sin((17pi)/6))

arcsin (sin (\frac{17 π}{6}))

\frac{π}{6}

Decimal Notation

30

Solution steps

arcsin (sin (\frac{17 π}{6}))

Use the inverse trig property:

\frac{π}{6}

arcsin (sin (\frac{17 π}{6}))

For

- \frac{π}{2} \leq x \leq \frac{π}{2}, a rcs in (s in (x)) = x

Rewrite using trig identities:

sin (\frac{17 π}{6}) = sin (\frac{5 π}{6})

sin (\frac{17 π}{6})

sin (x + 2 π \cdot k) = sin (x)

= sin (\frac{17 π}{6} - 1 \cdot 2 π)

= sin (\frac{5 π}{6})

= arcsin (sin (\frac{5 π}{6}))

Rewrite using trig identities:

sin (\frac{17 π}{6}) = sin (\frac{π}{6})

sin (\frac{17 π}{6})

sin (x) = sin (π - (x))

= sin (π - \frac{5 π}{6})

= sin (\frac{π}{6})

= arcsin (sin (\frac{π}{6}))

- \frac{π}{2} \leq \frac{π}{6} \leq \frac{π}{2}

= \frac{π}{6}

= \frac{π}{6}

cos^{2} (\frac{5 π}{4})

3 tan (4 5^{\circ}) + csc (3 0^{\circ}) cos (6 0^{\circ})

\frac{sin ( 4 7 ^{\circ} ) + cos ( 1 7 ^{\circ} )}{cos ( 4 7 ^{\circ} ) + sin ( 1 7 ^{\circ} )}

10 cos (7 5^{\circ}) cos (1 5^{\circ})

cos^{2} (\frac{5 π}{6}) - 2 sin (\frac{5 π}{6})

What is the value of arcsin(sin((17pi)/6)) ?
The value of arcsin(sin((17pi)/6)) is pi/6