What is the general solution for 2cos(x+pi/6)=1,0<x<2pi ?

Q: What is the general solution for 2cos(x+pi/6)=1,0<x<2pi ?

The general solution for 2cos(x+pi/6)=1,0<x<2pi is x= pi/6 ,x=(3pi)/2

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Popular Trigonometry >

2cos(x+pi/6)=1,0<x<2pi

Solution

2 cos (x + \frac{π}{6}) = 1, 0 < x < 2 π

Solution

x = \frac{π}{6}, x = \frac{3 π}{2}

Degrees

x = 3 0^{\circ}, x = 27 0^{\circ}

Solution steps

2 cos (x + \frac{π}{6}) = 1, 0 < x < 2 π

Divide both sides by

2

2 cos (x + \frac{π}{6}) = 1

Divide both sides by

2

\frac{2 cos ( x + \frac{π}{6} )}{2} = \frac{1}{2}

Simplify

cos (x + \frac{π}{6}) = \frac{1}{2}

cos (x + \frac{π}{6}) = \frac{1}{2}

General solutions for

cos (x + \frac{π}{6}) = \frac{1}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x + \frac{π}{6} = \frac{π}{3} + 2 πn, x + \frac{π}{6} = \frac{5 π}{3} + 2 πn

x + \frac{π}{6} = \frac{π}{3} + 2 πn, x + \frac{π}{6} = \frac{5 π}{3} + 2 πn

Solve

x + \frac{π}{6} = \frac{π}{3} + 2 πn : x = 2 πn + \frac{π}{6}

x + \frac{π}{6} = \frac{π}{3} + 2 πn

Move

\frac{π}{6}

to the right side

x + \frac{π}{6} = \frac{π}{3} + 2 πn

Subtract

\frac{π}{6}

from both sides

x + \frac{π}{6} - \frac{π}{6} = \frac{π}{3} + 2 πn - \frac{π}{6}

Simplify

x + \frac{π}{6} - \frac{π}{6} = \frac{π}{3} + 2 πn - \frac{π}{6}

Simplify

x + \frac{π}{6} - \frac{π}{6} : x

x + \frac{π}{6} - \frac{π}{6}

Add similar elements:

\frac{π}{6} - \frac{π}{6} = 0

= x

Simplify

\frac{π}{3} + 2 πn - \frac{π}{6} : 2 πn + \frac{π}{6}

\frac{π}{3} + 2 πn - \frac{π}{6}

Group like terms

= 2 πn + \frac{π}{3} - \frac{π}{6}

Least Common Multiplier of

3, 6 : 6

3, 6

Least Common Multiplier (LCM)

Prime factorization of

3 : 3

3

3

is a prime number, therefore no factorization is possible

= 3

Prime factorization of

6 : 2 \cdot 3

6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3

Multiply each factor the greatest number of times it occurs in either

3

6

= 3 \cdot 2

Multiply the numbers:

3 \cdot 2 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

\frac{π}{3} :

multiply the denominator and numerator by

2

\frac{π}{3} = \frac{π 2}{3 \cdot 2} = \frac{π 2}{6}

= \frac{π 2}{6} - \frac{π}{6}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{π 2 - π}{6}

Add similar elements:

2 π - π = π

= 2 πn + \frac{π}{6}

x = 2 πn + \frac{π}{6}

x = 2 πn + \frac{π}{6}

x = 2 πn + \frac{π}{6}

Solve

x + \frac{π}{6} = \frac{5 π}{3} + 2 πn : x = 2 πn + \frac{3 π}{2}

x + \frac{π}{6} = \frac{5 π}{3} + 2 πn

Move

\frac{π}{6}

to the right side

x + \frac{π}{6} = \frac{5 π}{3} + 2 πn

Subtract

\frac{π}{6}

from both sides

x + \frac{π}{6} - \frac{π}{6} = \frac{5 π}{3} + 2 πn - \frac{π}{6}

Simplify

x + \frac{π}{6} - \frac{π}{6} = \frac{5 π}{3} + 2 πn - \frac{π}{6}

Simplify

x + \frac{π}{6} - \frac{π}{6} : x

x + \frac{π}{6} - \frac{π}{6}

Add similar elements:

\frac{π}{6} - \frac{π}{6} = 0

= x

Simplify

\frac{5 π}{3} + 2 πn - \frac{π}{6} : 2 πn + \frac{3 π}{2}

\frac{5 π}{3} + 2 πn - \frac{π}{6}

Group like terms

= 2 πn - \frac{π}{6} + \frac{5 π}{3}

Least Common Multiplier of

6, 3 : 6

6, 3

Least Common Multiplier (LCM)

Prime factorization of

6 : 2 \cdot 3

6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3

Prime factorization of

3 : 3

3

3

is a prime number, therefore no factorization is possible

= 3

Multiply each factor the greatest number of times it occurs in either

6

3

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

\frac{5 π}{3} :

multiply the denominator and numerator by

2

\frac{5 π}{3} = \frac{5 π 2}{3 \cdot 2} = \frac{10 π}{6}

= - \frac{π}{6} + \frac{10 π}{6}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- π + 10 π}{6}

Add similar elements:

- π + 10 π = 9 π

= \frac{9 π}{6}

Cancel the common factor:

3

= 2 πn + \frac{3 π}{2}

x = 2 πn + \frac{3 π}{2}

x = 2 πn + \frac{3 π}{2}

x = 2 πn + \frac{3 π}{2}

x = 2 πn + \frac{π}{6}, x = 2 πn + \frac{3 π}{2}

Solutions for the range

0 < x < 2 π

x = \frac{π}{6}, x = \frac{3 π}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the general solution for 2cos(x+pi/6)=1,0<x<2pi ?
The general solution for 2cos(x+pi/6)=1,0<x<2pi is x= pi/6 ,x=(3pi)/2