What is the general solution for 2cos(x+pi/6)=1,0<x<2pi ?

The general solution for 2cos(x+pi/6)=1,0<x<2pi is x= pi/6 ,x=(3pi)/2

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2cos(x+pi/6)=1,0<x<2pi

2 cos (x + \frac{π}{6}) = 1, 0 < x < 2 π

x = \frac{π}{6}, x = \frac{3 π}{2}

Solution steps

2 cos (x + \frac{π}{6}) = 1, 0 < x < 2 π

Divide both sides by

2

cos (x + \frac{π}{6}) = \frac{1}{2}

General solutions for

cos (x + \frac{π}{6}) = \frac{1}{2}

x + \frac{π}{6} = \frac{π}{3} + 2 πn, x + \frac{π}{6} = \frac{5 π}{3} + 2 πn

Solve

x + \frac{π}{6} = \frac{π}{3} + 2 πn : x = 2 πn + \frac{π}{6}

Solve

x + \frac{π}{6} = \frac{5 π}{3} + 2 πn : x = 2 πn + \frac{3 π}{2}

x = 2 πn + \frac{π}{6}, x = 2 πn + \frac{3 π}{2}

Solutions for the range

0 < x < 2 π

x = \frac{π}{6}, x = \frac{3 π}{2}

tan (\frac{13 π}{4})

2 cos (x) + 3 = 0

sec^{2} (\frac{π}{4})

\frac{cos ( x )}{1 - sin ( x )} = sec (x) + tan (x)

arccsc (- 2)

What is the general solution for 2cos(x+pi/6)=1,0<x<2pi ?
The general solution for 2cos(x+pi/6)=1,0<x<2pi is x= pi/6 ,x=(3pi)/2