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Popular >

sin(2*2pi)

Solution

sin (2 \cdot 2 π)

Solution

0

Solution steps

sin (2 \cdot 2 π)

Simplify

= sin (4 π)

sin (4 π) = sin (0)

sin (4 π)

Rewrite

4 π

as

2 π \cdot 2 + 0

= sin (2 π 2 + 0)

Apply the periodicity of

sin

:

sin (x + 2 π \cdot k) = sin (x)

sin (2 π \cdot 2 + 0) = sin (0)

= sin (0)

= sin (0)

Use the following trivial identity:

sin (0) = 0

sin (0)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= 0

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Frequently Asked Questions (FAQ)

What is the value of sin(2*2pi) ?
The value of sin(2*2pi) is 0