What is the value of 10cos(-30) ?

The value of 10cos(-30) is 5sqrt(3)

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10cos(-30)

10 cos (- 3 0^{\circ})

53

Decimal Notation

8.66025 \dots

Solution steps

10 cos (- 3 0^{\circ})

Rewrite using trig identities:

cos (- 3 0^{\circ}) = \frac{3}{2}

cos (- 3 0^{\circ})

Use the following property:

cos (- x) = cos (x)

cos (- 3 0^{\circ}) = cos (3 0^{\circ})

= cos (3 0^{\circ})

Use the following trivial identity:

cos (3 0^{\circ}) = \frac{3}{2}

cos (3 0^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{3}{2}

= \frac{3}{2}

= 10 \cdot \frac{3}{2}

Simplify

10 \cdot \frac{3}{2} : 53

10 \cdot \frac{3}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 \cdot 10}{2}

Divide the numbers:

\frac{10}{2} = 5

= 53

= 53

2 + cos (0)

- 2 cos (\frac{2 π}{3})

- 3 + 4 cos (0)

arctan (\frac{20}{9.7})

cot (arctan (\frac{5}{8}))