What is the general solution for 2sin^2(x)-sin(x)-3=0 ?

The general solution for 2sin^2(x)-sin(x)-3=0 is x=(3pi)/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin^2(x)-sin(x)-3=0

2 sin^{2} (x) - sin (x) - 3 = 0

x = \frac{3 π}{2} + 2 πn

Solution steps

2 sin^{2} (x) - sin (x) - 3 = 0

Solve by substitution

sin (x) = \frac{3}{2}, sin (x) = - 1

sin (x) = \frac{3}{2} :

No Solution

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{3 π}{2} + 2 πn

sec (21 0^{\circ})

tan (x) + cot (x) = sec (x) csc (x)

sec (\frac{7 π}{6})

sec (\frac{π}{6})

2 cos^{2} (θ) + cos (θ) = 0

What is the general solution for 2sin^2(x)-sin(x)-3=0 ?
The general solution for 2sin^2(x)-sin(x)-3=0 is x=(3pi)/2+2pin