What is the general solution for sec((3θ)/2)=2 ?

The general solution for sec((3θ)/2)=2 is θ=(2pi)/9+(4pin)/3 ,θ=(10pi)/9+(4pin)/3

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sec((3θ)/2)=2

sec (\frac{3 θ}{2}) = 2

θ = \frac{2 π}{9} + \frac{4 πn}{3}, θ = \frac{10 π}{9} + \frac{4 πn}{3}

Solution steps

sec (\frac{3 θ}{2}) = 2

General solutions for

sec (\frac{3 θ}{2}) = 2

\frac{3 θ}{2} = \frac{π}{3} + 2 πn, \frac{3 θ}{2} = \frac{5 π}{3} + 2 πn

Solve

\frac{3 θ}{2} = \frac{π}{3} + 2 πn : θ = \frac{2 π}{9} + \frac{4 πn}{3}

Solve

\frac{3 θ}{2} = \frac{5 π}{3} + 2 πn : θ = \frac{10 π}{9} + \frac{4 πn}{3}

θ = \frac{2 π}{9} + \frac{4 πn}{3}, θ = \frac{10 π}{9} + \frac{4 πn}{3}

tan (arccos (\frac{2}{2}))

arccos (- 1)

sin (2)

sin (- \frac{1}{2})

3 cot (θ) + 1 = 0

What is the general solution for sec((3θ)/2)=2 ?
The general solution for sec((3θ)/2)=2 is θ=(2pi)/9+(4pin)/3 ,θ=(10pi)/9+(4pin)/3