What is the value of -2cos(-pi) ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-2cos(-pi)

- 2 cos (- π)

2

Solution steps

- 2 cos (- π)

Rewrite using trig identities:

cos (- π) = - 1

cos (- π)

Use the following property:

cos (- x) = cos (x)

cos (- π) = cos (π)

= cos (π)

Use the following trivial identity:

cos (π) = (- 1)

cos (π)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= (- 1)

= - 1

= - 2 (- 1)

Simplify

= 2

5 sin (2 0^{\circ})

sin (\frac{5}{4})

cot (- 31 5^{\circ})

cos (15 5^{\circ}) cos (3 5^{\circ}) + sin (15 5^{\circ}) sin (3 5^{\circ})

cos (24 0^{\circ} - 0^{\circ})