Is 1-cos^2(x)=(tan^2(x))/(sec^2(x)) ?

The answer to whether 1-cos^2(x)=(tan^2(x))/(sec^2(x)) is True

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prove 1-cos^2(x)=(tan^2(x))/(sec^2(x))

prove

1 - cos^{2} (x) = \frac{tan ^{2} ( x )}{sec ^{2} ( x )}

True

Solution steps

1 - cos^{2} (x) = \frac{tan ^{2} ( x )}{sec ^{2} ( x )}

Manipulating right side

\frac{tan ^{2} ( x )}{sec ^{2} ( x )}

Express with sin, cos

= sin^{2} (x)

Rewrite using trig identities

= 1 - cos^{2} (x)

We showed that the two sides could take the same form

\Rightarrow True

\frac{( cos ^{2} ( x ) )}{( 1 - sin ( x ) )} = 1 + sin (x)

8 csc^{2} (x) - 3 cot^{2} (x) = 3 + 5 csc^{2} (x)

sin^{2} (t) = (sin (t))^{2}

sin (2 x) - 2 cos (x) = 0, (0, 2 π)

sin (\frac{( 5 π )}{3})

Is 1-cos^2(x)=(tan^2(x))/(sec^2(x)) ?
The answer to whether 1-cos^2(x)=(tan^2(x))/(sec^2(x)) is True