What is the general solution for cos(15)= a/(55) ?

The general solution for cos(15)= a/(55) is a=(55(sqrt(6)+sqrt(2)))/4

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cos(15)= a/(55)

cos (1 5^{\circ}) = \frac{a}{55}

a = \frac{55 ( 6 + 2 )}{4}

Solution steps

cos (1 5^{\circ}) = \frac{a}{55}

Switch sides

\frac{a}{55} = cos (1 5^{\circ})

Simplify

cos (1 5^{\circ}) : \frac{6 + 2}{4}

\frac{a}{55} = \frac{6 + 2}{4}

Multiply both sides by

55

a = \frac{55 ( 6 + 2 )}{4}

tan^{0} (2 x + 15) = - 1

x = \frac{20}{sin ( 4 5 ^{\circ} )}

sin^{4} (u) - cos^{4} (u) = 2 sin^{2} (u) - 1

tan^{4} (x) - sec^{4} (x) = - 2 sec^{2} (x) + 1

(tan (x) + cot (x)) tan (x) = sec^{2} (x)

What is the general solution for cos(15)= a/(55) ?
The general solution for cos(15)= a/(55) is a=(55(sqrt(6)+sqrt(2)))/4