What is the general solution for sin(41)= x/(13) ?

The general solution for sin(41)= x/(13) is x=13sin(41)

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sin(41)= x/(13)

sin (4 1^{\circ}) = \frac{x}{13}

x = 13 sin (4 1^{\circ})

Solution steps

sin (4 1^{\circ}) = \frac{x}{13}

Switch sides

\frac{x}{13} = sin (4 1^{\circ})

Multiply both sides by

13

x = 13 sin (4 1^{\circ})

i, sin (x) = cos (9 0^{\circ} - x)

t, 1 + tan (\frac{a}{1}) - tan (a) = tan (4 5^{\circ} + a)

x = a sin (0)

c, d^{4} + 1 = cosh (x) + sinh^{3} (x)

c, cos (3 x) - cos (x) = sin (3 x) - sin (x)

What is the general solution for sin(41)= x/(13) ?
The general solution for sin(41)= x/(13) is x=13sin(41)