zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

y=(arcsin(1))/2

解答

y = \frac{arcsin ( 1 )}{2}

解答

y = \frac{π}{4}

+1

十进制

y = 0.78539 \dots

求解步骤

y = \frac{arcsin ( 1 )}{2}

化简

\frac{arcsin ( 1 )}{2} : \frac{π}{4}

\frac{arcsin ( 1 )}{2}

arcsin (1) = \frac{π}{2}

arcsin (1)

使用以下普通恒等式:

arcsin (1) = \frac{π}{2}

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= \frac{π}{2}

= \frac{\frac{π}{2}}{2}

化简

\frac{\frac{π}{2}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{2 \cdot 2}

数字相乘:

2 \cdot 2 = 4

= \frac{π}{4}

y = \frac{π}{4}

y = \frac{π}{4}

作图

流行的例子

solvefor k,sqrt(x^2+y^2)=k*arctan(y/x)

so l v e f or k, x^{2} + y^{2} = k \cdot arctan (\frac{y}{x})

solvefor t,cot(90^0+x)=tan(x)

so l v e f or t, cot (9 0^{0} + x) = tan (x)

solvefor t,arccos(((5cos(x)+3))/((5+3cos(x))))=2arctan(1/2*tan(x/2))

so l v e f or t, arccos (\frac{( 5 cos ( x ) + 3 )}{( 5 + 3 cos ( x ) )}) = 2 arctan (\frac{1}{2} \cdot tan (\frac{x}{2}))

solvefor x,y=cos(y/(1.75))+x-0.5y^2

so l v e f or x, y = cos (\frac{y}{1.75}) + x - 0.5 y^{2}

solvefor c,2sin^3(x)+cos^2(x)-cos(x)=0

so l v e f or c, 2 sin^{3} (x) + cos^{2} (x) - cos (x) = 0