What is the general solution for solvefor t,tan(x)tan^2(x)=1 ?

The general solution for solvefor t,tan(x)tan^2(x)=1 is True for all t;\quad tan^3(x)=1

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solvefor t,tan(x)tan^2(x)=1

solve for

t, tan (x) tan^{2} (x) = 1

True for all t; tan^{3} (x) = 1

Solution steps

tan (x) tan^{2} (x) = 1

Simplify

tan (x) tan^{2} (x) : tan^{3} (x)

tan^{3} (x) = 1

Both sides are equal

True for all t; tan^{3} (x) = 1

t, tan (a) + tan (b) = 2 tan (a + b)

t, tan (b) = sin (a) cos (\frac{a}{2}) + cos^{2} (a)

c, cos^{2} (x) - 4 sin (x) + 2 cos (x) - 3 = 0

f, (a + f) = a \cdot cosh (\frac{l}{( 2 a )})

t, tan (4 5^{\circ} + \frac{a}{2}) = sec (a) + tan (a)

What is the general solution for solvefor t,tan(x)tan^2(x)=1 ?
The general solution for solvefor t,tan(x)tan^2(x)=1 is True for all t;\quad tan^3(x)=1