What is the general solution for solvefor t,cot(x)cot^2(x)=-1 ?

The general solution for solvefor t,cot(x)cot^2(x)=-1 is True for all t;\quad cot^3(x)=-1

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solvefor t,cot(x)cot^2(x)=-1

solve for

t, cot (x) cot^{2} (x) = - 1

True for all t; cot^{3} (x) = - 1

Solution steps

cot (x) cot^{2} (x) = - 1

Simplify

cot (x) cot^{2} (x) : cot^{3} (x)

cot^{3} (x) = - 1

Both sides are equal

True for all t; cot^{3} (x) = - 1

i, 1 - 2 sin^{2} (4 5^{\circ} - \frac{a}{2}) = sin (a)

c, sin^{2} (x) + sin (x) - cos (x) + \frac{1}{2} = 0

c, cos^{4} (s) - sin^{4} (x) + 1 + cos (x) = 0

c, cot^{2} (x) = cos (x) + sin (x)

y, y = sin (3 t) u (t) \cdot u (t)

What is the general solution for solvefor t,cot(x)cot^2(x)=-1 ?
The general solution for solvefor t,cot(x)cot^2(x)=-1 is True for all t;\quad cot^3(x)=-1