What is the general solution for sin^2(a)=1-cos(2a) ?

The general solution for sin^2(a)=1-cos(2a) is a=2pin,a=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin^2(a)=1-cos(2a)

sin^{2} (a) = 1 - cos (2 a)

a = 2 πn, a = π + 2 πn

Solution steps

sin^{2} (a) = 1 - cos (2 a)

Subtract

1 - cos (2 a)

from both sides

sin^{2} (a) - 1 + cos (2 a) = 0

Rewrite using trig identities

- 1 + cos^{2} (a) = 0

Solve by substitution

cos (a) = 1, cos (a) = - 1

cos (a) = 1 : a = 2 πn

cos (a) = - 1 : a = π + 2 πn

Combine all the solutions

a = 2 πn, a = π + 2 πn

cos^{4} (x) = cos^{2} (x)

tan (x) = 2 + tan^{3} (x)

2 \cdot sin (a) = sin (3 a)

\frac{cos ( x ) + 5 sin ( x )}{2 - 3} = 0

sin (y) = \frac{2}{3}

What is the general solution for sin^2(a)=1-cos(2a) ?
The general solution for sin^2(a)=1-cos(2a) is a=2pin,a=pi+2pin