What is the general solution for tan^2(a)=((2tan(a)))/((1-tan^2(a))) ?

The general solution for tan^2(a)=((2tan(a)))/((1-tan^2(a))) is a=pin,a=-0.98930…+pin

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tan^2(a)=((2tan(a)))/((1-tan^2(a)))

tan^{2} (a) = \frac{( 2 tan ( a ) )}{( 1 - tan ^{2} ( a ) )}

a = πn, a = - 0.98930 \dots + πn

Solution steps

tan^{2} (a) = \frac{( 2 tan ( a ) )}{( 1 - tan ^{2} ( a ) )}

Solve by substitution

tan (a) = 0, tan (a) \approx - 1.52137 \dots

tan (a) = 0 : a = πn

tan (a) = - 1.52137 \dots : a = arctan (- 1.52137 \dots) + πn

Combine all the solutions

a = πn, a = arctan (- 1.52137 \dots) + πn

Show solutions in decimal form

a = πn, a = - 0.98930 \dots + πn

12 cos^{2} (x) - 6 = sin (x)

cos^{2} (a) = \frac{2}{3}

sin (2 x) = - 0.848055484

2 + cos^{2} (x) = 3 cos (x)

cos (x + 4 0^{\circ}) = 0.85

What is the general solution for tan^2(a)=((2tan(a)))/((1-tan^2(a))) ?
The general solution for tan^2(a)=((2tan(a)))/((1-tan^2(a))) is a=pin,a=-0.98930…+pin