What is the general solution for cos(x-15^0)=((sqrt(2)))/2 ?

The general solution for cos(x-15^0)=((sqrt(2)))/2 is x= pi/4+2pin+1,x=(7pi)/4+2pin+1

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cos(x-15^0)=((sqrt(2)))/2

cos (x - 1 5^{0}) = \frac{( 2 )}{2}

x = \frac{π}{4} + 2 πn + 1, x = \frac{7 π}{4} + 2 πn + 1

Solution steps

cos (x - 1 5^{0}) = \frac{( 2 )}{2}

General solutions for

cos (x - 1 5^{0}) = \frac{2}{2}

x - 1 5^{0} = \frac{π}{4} + 2 πn, x - 1 5^{0} = \frac{7 π}{4} + 2 πn

Solve

x - 1 5^{0} = \frac{π}{4} + 2 πn : x = \frac{π}{4} + 2 πn + 1

Solve

x - 1 5^{0} = \frac{7 π}{4} + 2 πn : x = \frac{7 π}{4} + 2 πn + 1

x = \frac{π}{4} + 2 πn + 1, x = \frac{7 π}{4} + 2 πn + 1

sin (x) = 1 - cos^{x} (x)

4 - 7 sin (x) = cos^{2} (x)

(d^{2} - 2 d + 3) = sin (x)

\frac{5}{tan ( x )} = - 2

tan^{22} (x) = sec^{2} (x) - 1

What is the general solution for cos(x-15^0)=((sqrt(2)))/2 ?
The general solution for cos(x-15^0)=((sqrt(2)))/2 is x= pi/4+2pin+1,x=(7pi)/4+2pin+1