What is the general solution for cos^4(x)-2cos^2(x)+1=0 ?

The general solution for cos^4(x)-2cos^2(x)+1=0 is x=2pin,x=pi+2pin

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cos^4(x)-2cos^2(x)+1=0

cos^{4} (x) - 2 cos^{2} (x) + 1 = 0

x = 2 πn, x = π + 2 πn

Solution steps

cos^{4} (x) - 2 cos^{2} (x) + 1 = 0

Solve by substitution

cos (x) = 1, cos (x) = - 1

cos (x) = 1 : x = 2 πn

cos (x) = - 1 : x = π + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn

sin^{2} (x) + cos^{2} (x) + cos (x) = 2

\frac{sin ^{3} ( x )}{sin ( x )} = 0

sin (135 - x) = sin (x)

tan (x) - 4 = - 1

4 cos^{2} (x) - 8 cos (x) + 3 = 0

What is the general solution for cos^4(x)-2cos^2(x)+1=0 ?
The general solution for cos^4(x)-2cos^2(x)+1=0 is x=2pin,x=pi+2pin