What is the general solution for 2cos^2(x)+3sin^2(x)=2 ?

The general solution for 2cos^2(x)+3sin^2(x)=2 is x=2pin,x=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos^2(x)+3sin^2(x)=2

2 cos^{2} (x) + 3 sin^{2} (x) = 2

x = 2 πn, x = π + 2 πn

Solution steps

2 cos^{2} (x) + 3 sin^{2} (x) = 2

Subtract

2

from both sides

2 cos^{2} (x) + 3 sin^{2} (x) - 2 = 0

Rewrite using trig identities

sin^{2} (x) = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

sin (x) = 0

General solutions for

sin (x) = 0

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 2 πn, x = π + 2 πn

42 - 25 cos (x) = 31

2 sec^{2} (x) = 5 tan (x)

cos^{2} (2 x) - 3 sin^{2} (x) - 1 = 0

sin (- t) = \frac{3}{10}

cos^{2} (x) + sin^{3} (x) = 0

What is the general solution for 2cos^2(x)+3sin^2(x)=2 ?
The general solution for 2cos^2(x)+3sin^2(x)=2 is x=2pin,x=pi+2pin