What is the general solution for 2cos(θ)+sqrt(2)=0 ?

The general solution for 2cos(θ)+sqrt(2)=0 is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin

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2cos(θ)+sqrt(2)=0

2 cos (θ) + 2 = 0

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

Solution steps

2 cos (θ) + 2 = 0

Move

2

to the right side

2 cos (θ) = - 2

Divide both sides by

2

cos (θ) = - \frac{2}{2}

General solutions for

cos (θ) = - \frac{2}{2}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

2 sin^{2} (x) - cos (x) - 1 = 0

cos (\frac{1}{2})

cos (x) = 0.4

arctan (tan (\frac{2 π}{3}))

cos (- \frac{2 π}{3})

What is the general solution for 2cos(θ)+sqrt(2)=0 ?
The general solution for 2cos(θ)+sqrt(2)=0 is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin