What is the general solution for arctan(x+2)=arcsin(7/25)+arccos(4/5) ?

The general solution for arctan(x+2)=arcsin(7/25)+arccos(4/5) is x=-2/3

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arctan(x+2)=arcsin(7/25)+arccos(4/5)

arctan (x + 2) = arcsin (\frac{7}{25}) + arccos (\frac{4}{5})

x = - \frac{2}{3}

Solution steps

arctan (x + 2) = arcsin (\frac{7}{25}) + arccos (\frac{4}{5})

Apply trig inverse properties

x + 2 = \frac{4}{3}

Solve

x + 2 = \frac{4}{3} : x = - \frac{2}{3}

x = - \frac{2}{3}

sec (a) = \frac{38}{13}

tan (c) = 0.6538

(sec^{2} (a)) cos^{2} (a) = sin^{2} (a)

- 2 sin (x) + 5 sin^{2} (x) = 0

3 \cdot tan^{2} (x) - 1 = 0

What is the general solution for arctan(x+2)=arcsin(7/25)+arccos(4/5) ?
The general solution for arctan(x+2)=arcsin(7/25)+arccos(4/5) is x=-2/3