What is the value of -sin(-pi/6) ?

The value of -sin(-pi/6) is 1/2

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-sin(-pi/6)

- sin (- \frac{π}{6})

\frac{1}{2}

Decimal Notation

0.5

Solution steps

- sin (- \frac{π}{6})

Rewrite using trig identities:

sin (- \frac{π}{6}) = - \frac{1}{2}

sin (- \frac{π}{6})

Use the following property:

sin (- x) = - sin (x)

sin (- \frac{π}{6}) = - sin (\frac{π}{6})

= - sin (\frac{π}{6})

Use the following trivial identity:

sin (\frac{π}{6}) = \frac{1}{2}

sin (\frac{π}{6})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= - \frac{1}{2}

= - (- \frac{1}{2})

Simplify

= \frac{1}{2}

arcsin (- 8)

4 sin (\frac{5 π}{3})

2 sin (\frac{π}{3}) - 3 tan (\frac{π}{6})

cos (10 5^{\circ}) sin (1 5^{\circ})

40 \cdot cos (6 0^{\circ})