What is the general solution for sin(60-x)-sin(60+x)=(sqrt(3))/2 ?

The general solution for sin(60-x)-sin(60+x)=(sqrt(3))/2 is x=-60-360n,x=-120-360n

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sin(60-x)-sin(60+x)=(sqrt(3))/2

sin (6 0^{\circ} - x) - sin (6 0^{\circ} + x) = \frac{3}{2}

x = - 6 0^{\circ} - 36 0^{\circ} n, x = - 12 0^{\circ} - 36 0^{\circ} n

Solution steps

sin (6 0^{\circ} - x) - sin (6 0^{\circ} + x) = \frac{3}{2}

Rewrite using trig identities

sin (- x) = \frac{3}{2}

General solutions for

sin (- x) = \frac{3}{2}

- x = 6 0^{\circ} + 36 0^{\circ} n, - x = 12 0^{\circ} + 36 0^{\circ} n

Solve

- x = 6 0^{\circ} + 36 0^{\circ} n : x = - 6 0^{\circ} - 36 0^{\circ} n

Solve

- x = 12 0^{\circ} + 36 0^{\circ} n : x = - 12 0^{\circ} - 36 0^{\circ} n

x = - 6 0^{\circ} - 36 0^{\circ} n, x = - 12 0^{\circ} - 36 0^{\circ} n

tan (\frac{x}{4}) + 3 = 0, 0 \leq x \leq 2 π

cot^{(2)} (x) - csc (x) - 1 = 0

4 sin (x) + 1 = 3 csc (x)

cos^{2} (x) - 3 sin (x) = 0

csc (t) = \frac{1}{- \frac{2}{2}}

What is the general solution for sin(60-x)-sin(60+x)=(sqrt(3))/2 ?
The general solution for sin(60-x)-sin(60+x)=(sqrt(3))/2 is x=-60-360n,x=-120-360n