What is the general solution for -(cos(x)-sin(x))/(1+sin(2x))=0 ?

The general solution for -(cos(x)-sin(x))/(1+sin(2x))=0 is x= pi/4+pin

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-(cos(x)-sin(x))/(1+sin(2x))=0

- \frac{cos ( x ) - sin ( x )}{1 + sin ( 2 x )} = 0

x = \frac{π}{4} + πn

Solution steps

- \frac{cos ( x ) - sin ( x )}{1 + sin ( 2 x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- (cos (x) - sin (x)) = 0

Rewrite using trig identities

- 1 + tan (x) = 0

Move

1

to the right side

tan (x) = 1

General solutions for

tan (x) = 1

x = \frac{π}{4} + πn

2 cos (x) = cot (x)

tan (x) = \frac{60}{\frac{( - 20 - 90 )}{2}}

0.1 \cdot sin (θ) cos (53.1 3^{\circ}) + 0.1 \cdot sin (θ) = 0

tan (θ) = (1)

sec^{2} (x) = \frac{3 3}{π}

What is the general solution for -(cos(x)-sin(x))/(1+sin(2x))=0 ?
The general solution for -(cos(x)-sin(x))/(1+sin(2x))=0 is x= pi/4+pin