What is the general solution for -1-cos(θ)=-3cos(θ) ?

The general solution for -1-cos(θ)=-3cos(θ) is θ= pi/3+2pin,θ=(5pi)/3+2pin

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-1-cos(θ)=-3cos(θ)

- 1 - cos (θ) = - 3 cos (θ)

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Solution steps

- 1 - cos (θ) = - 3 cos (θ)

Solve by substitution

cos (θ) = \frac{1}{2}

cos (θ) = \frac{1}{2} : θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Combine all the solutions

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

3 \cdot cos (θ) = 2 - sin (θ)

0.06 = 0.1 \cdot cos (4 x - 1.57)

tan (a) = \frac{20}{15}

sin (x) = - \frac{8}{8 13}

cos (x) = 1.76819

What is the general solution for -1-cos(θ)=-3cos(θ) ?
The general solution for -1-cos(θ)=-3cos(θ) is θ= pi/3+2pin,θ=(5pi)/3+2pin