What is the general solution for 0=-6sin(x)+6cos(2x) ?

The general solution for 0=-6sin(x)+6cos(2x) is x=(3pi)/2+2pin,x= pi/6+2pin,x=(5pi)/6+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0=-6sin(x)+6cos(2x)

0 = - 6 sin (x) + 6 cos (2 x)

x = \frac{3 π}{2} + 2 πn, x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Solution steps

0 = - 6 sin (x) + 6 cos (2 x)

Switch sides

- 6 sin (x) + 6 cos (2 x) = 0

Rewrite using trig identities

(1 - 2 sin^{2} (x)) \cdot 6 - 6 sin (x) = 0

Solve by substitution

sin (x) = - 1, sin (x) = \frac{1}{2}

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

sin (x) = \frac{1}{2} : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Combine all the solutions

x = \frac{3 π}{2} + 2 πn, x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

tan (2 x + 1) = \frac{1}{2}

cos (B) = \frac{8}{12}

sin (t) = \frac{1}{2}, 0 \leq t < \frac{π}{2}

tan (θ) = 1.4

sin (θ) = - 0.8062

What is the general solution for 0=-6sin(x)+6cos(2x) ?
The general solution for 0=-6sin(x)+6cos(2x) is x=(3pi)/2+2pin,x= pi/6+2pin,x=(5pi)/6+2pin