What is the general solution for cos^2(θ)-3cos(θ)+2=0 ?

The general solution for cos^2(θ)-3cos(θ)+2=0 is θ=2pin

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cos^2(θ)-3cos(θ)+2=0

cos^{2} (θ) - 3 cos (θ) + 2 = 0

θ = 2 πn

Solution steps

cos^{2} (θ) - 3 cos (θ) + 2 = 0

Solve by substitution

cos (θ) = 2, cos (θ) = 1

cos (θ) = 2 :

No Solution

cos (θ) = 1 : θ = 2 πn

Combine all the solutions

θ = 2 πn

cos (2 x - \frac{π}{6}) = - \frac{1}{2}, \frac{π}{2} \leq x < π

\frac{( sin ( x ) )}{( 4.2 )} = \frac{( sin ( 9 5 ^{\circ} ) )}{( 10.26 )}

- sin (x) = - cos (x)

t, f = sin (k t)

6 sin (θ) = 3 + 3 sin (θ)

What is the general solution for cos^2(θ)-3cos(θ)+2=0 ?
The general solution for cos^2(θ)-3cos(θ)+2=0 is θ=2pin