What is the general solution for solvefor θ,w=fdcos(θ) ?

The general solution for solvefor θ,w=fdcos(θ) is θ=arccos(w/(fd))+2pin,θ=-arccos(w/(fd))+2pin

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solvefor θ,w=fdcos(θ)

solve for

θ, w = fd cos (θ)

θ = arccos (\frac{w}{fd}) + 2 πn, θ = - arccos (\frac{w}{fd}) + 2 πn

Solution steps

w = fd cos (θ)

Switch sides

fd cos (θ) = w

Divide both sides by

fd; fd \neq = 0

cos (θ) = \frac{w}{fd}; fd \neq = 0

Apply trig inverse properties

θ = arccos (\frac{w}{fd}) + 2 πn, θ = - arccos (\frac{w}{fd}) + 2 πn

sec (x) - sec (x) tan (x) = 0

4 sin^{2} (x) = 3, 0 \leq x \leq 18 0^{\circ}

sin (x + 3 0^{\circ}) = 2 cos (x)

(3 cos (x) + 2 sin (x))^{2} + 5 sin^{2} (x) = 9 - 33

7 cos (2 x) = 7 sin^{2} (x) + 5

What is the general solution for solvefor θ,w=fdcos(θ) ?
The general solution for solvefor θ,w=fdcos(θ) is θ=arccos(w/(fd))+2pin,θ=-arccos(w/(fd))+2pin