What is the general solution for 4sin^2(x)+2sin(x)=0 ?

The general solution for 4sin^2(x)+2sin(x)=0 is x=2pin,x=pi+2pin,x=(7pi)/6+2pin,x=(11pi)/6+2pin

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4sin^2(x)+2sin(x)=0

4 sin^{2} (x) + 2 sin (x) = 0

x = 2 πn, x = π + 2 πn, x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solution steps

4 sin^{2} (x) + 2 sin (x) = 0

Solve by substitution

sin (x) = 0, sin (x) = - \frac{1}{2}

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = - \frac{1}{2} : x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

tan (x) = 3, - \frac{π}{3} \leq x \leq \frac{3 π}{2}

sin (x) = \frac{5}{16}

sin^{2} (x) + 2 cos (x) = 0

sin (a) = 0.36

sin (a) = 0.35

What is the general solution for 4sin^2(x)+2sin(x)=0 ?
The general solution for 4sin^2(x)+2sin(x)=0 is x=2pin,x=pi+2pin,x=(7pi)/6+2pin,x=(11pi)/6+2pin