What is the general solution for cos(pi/2+x)-cos(pi/2-x)=-sqrt(3) ?

The general solution for cos(pi/2+x)-cos(pi/2-x)=-sqrt(3) is x= pi/3+2pin,x=(2pi)/3+2pin

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cos(pi/2+x)-cos(pi/2-x)=-sqrt(3)

cos (\frac{π}{2} + x) - cos (\frac{π}{2} - x) = - 3

x = \frac{π}{3} + 2 πn, x = \frac{2 π}{3} + 2 πn

Solution steps

cos (\frac{π}{2} + x) - cos (\frac{π}{2} - x) = - 3

Rewrite using trig identities

- 2 sin (x) = - 3

Divide both sides by

- 2

sin (x) = \frac{3}{2}

General solutions for

sin (x) = \frac{3}{2}

x = \frac{π}{3} + 2 πn, x = \frac{2 π}{3} + 2 πn

tan (x) = 2.142

3 cos (θ) = - 2

sin (x) = \frac{20}{38.59}

sec (A) = 5.29411

sin (x) = \frac{5}{19}

What is the general solution for cos(pi/2+x)-cos(pi/2-x)=-sqrt(3) ?
The general solution for cos(pi/2+x)-cos(pi/2-x)=-sqrt(3) is x= pi/3+2pin,x=(2pi)/3+2pin