What is the general solution for sin(x)sin(x)=0 ?

The general solution for sin(x)sin(x)=0 is x=2pin,x=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(x)sin(x)=0

sin (x) sin (x) = 0

x = 2 πn, x = π + 2 πn

Solution steps

sin (x) sin (x) = 0

Simplify

sin (x) sin (x) : sin^{2} (x)

sin^{2} (x) = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

sin (x) = 0

General solutions for

sin (x) = 0

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 2 πn, x = π + 2 πn

15 = arctan (\frac{0.375}{2 x})

cos (θ) (1 + cos (θ)) = sin^{2} (θ)

cos (θ) = - 0.8, sin (π^{2} - θ)

0 = a (1 + cos (2 θ))

4 sin (2 x) = 3 cos (x)

What is the general solution for sin(x)sin(x)=0 ?
The general solution for sin(x)sin(x)=0 is x=2pin,x=pi+2pin