What is the general solution for 5cos(x)-3=9cos(x)-5 ?

The general solution for 5cos(x)-3=9cos(x)-5 is x= pi/3+2pin,x=(5pi)/3+2pin

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5cos(x)-3=9cos(x)-5

5 cos (x) - 3 = 9 cos (x) - 5

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solution steps

5 cos (x) - 3 = 9 cos (x) - 5

Solve by substitution

cos (x) = \frac{1}{2}

cos (x) = \frac{1}{2} : x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Combine all the solutions

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

3 sin^{2} (x) - 8 sin (x) + 4 = 0

3 tan (x) = tan (2 x)

cos (4 x) + sin (6 x) = 0

- 15.44 = - 2 sin (- 3 θ + 300)

sin (x) = - cos (3 4^{\circ})

What is the general solution for 5cos(x)-3=9cos(x)-5 ?
The general solution for 5cos(x)-3=9cos(x)-5 is x= pi/3+2pin,x=(5pi)/3+2pin