What is the general solution for solvefor x,sin(x)-cos(x)=1 ?

The general solution for solvefor x,sin(x)-cos(x)=1 is x= pi/2+2pin,x=2pin+pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,sin(x)-cos(x)=1

solve for

x, sin (x) - cos (x) = 1

x = \frac{π}{2} + 2 πn, x = 2 πn + π

Solution steps

sin (x) - cos (x) = 1

Rewrite using trig identities

2 sin (x - \frac{π}{4}) = 1

Divide both sides by

2

sin (x - \frac{π}{4}) = \frac{2}{2}

General solutions for

sin (x - \frac{π}{4}) = \frac{2}{2}

x - \frac{π}{4} = \frac{π}{4} + 2 πn, x - \frac{π}{4} = \frac{3 π}{4} + 2 πn

Solve

x - \frac{π}{4} = \frac{π}{4} + 2 πn : x = \frac{π}{2} + 2 πn

Solve

x - \frac{π}{4} = \frac{3 π}{4} + 2 πn : x = 2 πn + π

x = \frac{π}{2} + 2 πn, x = 2 πn + π

x, sin (x) cos (y) = 1

sin (4 x) cos (7 x) - cos (4 x) sin (7 x) = - 0.6

cos (x) = \frac{40}{41}

sin (x) + cos (x) = 4

x, ln (y) = sin (x)

What is the general solution for solvefor x,sin(x)-cos(x)=1 ?
The general solution for solvefor x,sin(x)-cos(x)=1 is x= pi/2+2pin,x=2pin+pi