What is the value of cos(120)+tan^2(240)-5 ?

The value of cos(120)+tan^2(240)-5 is -5/2

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cos(120)+tan^2(240)-5

cos (12 0^{\circ}) + tan^{2} (24 0^{\circ}) - 5

- \frac{5}{2}

Solution steps

cos (12 0^{\circ}) + tan^{2} (24 0^{\circ}) - 5

Use the following trivial identity:

cos (12 0^{\circ}) = - \frac{1}{2}

Rewrite using trig identities:

tan (24 0^{\circ}) = 3

= - \frac{1}{2} + (3)^{2} - 5

Simplify

- \frac{1}{2} + (3)^{2} - 5 : - \frac{5}{2}

= - \frac{5}{2}

\frac{cos ( 6 0 ^{\circ} )}{cos ( 4 5 ^{\circ} )}

arctan (tan (\frac{5 π}{7}))

sin^{3} (1)

sin (\frac{π ^{2}}{9})

\frac{12}{sin ( 4 5 ^{\circ} )}

What is the value of cos(120)+tan^2(240)-5 ?
The value of cos(120)+tan^2(240)-5 is -5/2