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Popular Trigonometry >

3sin(θ)cos(θ)=sin(θ)

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Solution

3sin(θ)cos(θ)=sin(θ)

Solution

θ=2πn,θ=π+2πn,θ=1.23095…+2πn,θ=2π−1.23095…+2πn
+1
Degrees
θ=0∘+360∘n,θ=180∘+360∘n,θ=70.52877…∘+360∘n,θ=289.47122…∘+360∘n
Solution steps
3sin(θ)cos(θ)=sin(θ)
Subtract sin(θ) from both sides3sin(θ)cos(θ)−sin(θ)=0
Factor 3sin(θ)cos(θ)−sin(θ):sin(θ)(3cos(θ)−1)
3sin(θ)cos(θ)−sin(θ)
Factor out common term sin(θ)=sin(θ)(3cos(θ)−1)
sin(θ)(3cos(θ)−1)=0
Solving each part separatelysin(θ)=0or3cos(θ)−1=0
sin(θ)=0:θ=2πn,θ=π+2πn
sin(θ)=0
General solutions for sin(θ)=0
sin(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​sin(x)021​22​​23​​123​​22​​21​​xπ67π​45π​34π​23π​35π​47π​611π​​sin(x)0−21​−22​​−23​​−1−23​​−22​​−21​​​
θ=0+2πn,θ=π+2πn
θ=0+2πn,θ=π+2πn
Solve θ=0+2πn:θ=2πn
θ=0+2πn
0+2πn=2πnθ=2πn
θ=2πn,θ=π+2πn
3cos(θ)−1=0:θ=arccos(31​)+2πn,θ=2π−arccos(31​)+2πn
3cos(θ)−1=0
Move 1to the right side
3cos(θ)−1=0
Add 1 to both sides3cos(θ)−1+1=0+1
Simplify3cos(θ)=1
3cos(θ)=1
Divide both sides by 3
3cos(θ)=1
Divide both sides by 333cos(θ)​=31​
Simplifycos(θ)=31​
cos(θ)=31​
Apply trig inverse properties
cos(θ)=31​
General solutions for cos(θ)=31​cos(x)=a⇒x=arccos(a)+2πn,x=2π−arccos(a)+2πnθ=arccos(31​)+2πn,θ=2π−arccos(31​)+2πn
θ=arccos(31​)+2πn,θ=2π−arccos(31​)+2πn
Combine all the solutionsθ=2πn,θ=π+2πn,θ=arccos(31​)+2πn,θ=2π−arccos(31​)+2πn
Show solutions in decimal formθ=2πn,θ=π+2πn,θ=1.23095…+2πn,θ=2π−1.23095…+2πn

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