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受欢迎的三角函数 >

cos(-x)=(sqrt(3))/2

解答

cos (- x) = \frac{3}{2}

解答

x = - \frac{π}{6} - 2 πn, x = - \frac{11 π}{6} - 2 πn

+1

度数

x = - 3 0^{\circ} - 36 0^{\circ} n, x = - 33 0^{\circ} - 36 0^{\circ} n

求解步骤

cos (- x) = \frac{3}{2}

cos (- x) = \frac{3}{2}

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

- x = \frac{π}{6} + 2 πn, - x = \frac{11 π}{6} + 2 πn

- x = \frac{π}{6} + 2 πn, - x = \frac{11 π}{6} + 2 πn

解

- x = \frac{π}{6} + 2 πn : x = - \frac{π}{6} - 2 πn

- x = \frac{π}{6} + 2 πn

两边除以

- 1

- x = \frac{π}{6} + 2 πn

两边除以

- 1

\frac{- x}{- 1} = \frac{\frac{π}{6}}{- 1} + \frac{2 πn}{- 1}

化简

\frac{- x}{- 1} = \frac{\frac{π}{6}}{- 1} + \frac{2 πn}{- 1}

化简

\frac{- x}{- 1} : x

\frac{- x}{- 1}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{x}{1}

使用法则

\frac{a}{1} = a

= x

化简

\frac{\frac{π}{6}}{- 1} + \frac{2 πn}{- 1} : - \frac{π}{6} - 2 πn

\frac{\frac{π}{6}}{- 1} + \frac{2 πn}{- 1}

\frac{\frac{π}{6}}{- 1} = - \frac{π}{6}

\frac{\frac{π}{6}}{- 1}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{\frac{π}{6}}{1}

使用分式法则:

\frac{a}{1} = a

\frac{\frac{π}{6}}{1} = \frac{π}{6}

= - \frac{π}{6}

= - \frac{π}{6} + \frac{2 πn}{- 1}

\frac{2 πn}{- 1} = - 2 πn

\frac{2 πn}{- 1}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{2 πn}{1}

使用法则

\frac{a}{1} = a

= - 2 πn

= - \frac{π}{6} - 2 πn

x = - \frac{π}{6} - 2 πn

x = - \frac{π}{6} - 2 πn

x = - \frac{π}{6} - 2 πn

解

- x = \frac{11 π}{6} + 2 πn : x = - \frac{11 π}{6} - 2 πn

- x = \frac{11 π}{6} + 2 πn

两边除以

- 1

- x = \frac{11 π}{6} + 2 πn

两边除以

- 1

\frac{- x}{- 1} = \frac{\frac{11 π}{6}}{- 1} + \frac{2 πn}{- 1}

化简

\frac{- x}{- 1} = \frac{\frac{11 π}{6}}{- 1} + \frac{2 πn}{- 1}

化简

\frac{- x}{- 1} : x

\frac{- x}{- 1}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{x}{1}

使用法则

\frac{a}{1} = a

= x

化简

\frac{\frac{11 π}{6}}{- 1} + \frac{2 πn}{- 1} : - \frac{11 π}{6} - 2 πn

\frac{\frac{11 π}{6}}{- 1} + \frac{2 πn}{- 1}

\frac{\frac{11 π}{6}}{- 1} = - \frac{11 π}{6}

\frac{\frac{11 π}{6}}{- 1}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{\frac{11 π}{6}}{1}

使用分式法则:

\frac{a}{1} = a

\frac{\frac{11 π}{6}}{1} = \frac{11 π}{6}

= - \frac{11 π}{6}

= - \frac{11 π}{6} + \frac{2 πn}{- 1}

\frac{2 πn}{- 1} = - 2 πn

\frac{2 πn}{- 1}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{2 πn}{1}

使用法则

\frac{a}{1} = a

= - 2 πn

= - \frac{11 π}{6} - 2 πn

x = - \frac{11 π}{6} - 2 πn

x = - \frac{11 π}{6} - 2 πn

x = - \frac{11 π}{6} - 2 πn

x = - \frac{π}{6} - 2 πn, x = - \frac{11 π}{6} - 2 πn

作图

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