What is the general solution for 12sin(A)+4=4sin(A)+4 ?

The general solution for 12sin(A)+4=4sin(A)+4 is A=2pin,A=pi+2pin

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12sin(A)+4=4sin(A)+4

12 sin (A) + 4 = 4 sin (A) + 4

A = 2 πn, A = π + 2 πn

Solution steps

12 sin (A) + 4 = 4 sin (A) + 4

Solve by substitution

sin (A) = 0

sin (A) = 0 : A = 2 πn, A = π + 2 πn

Combine all the solutions

A = 2 πn, A = π + 2 πn

2 sin^{2} (x) = 3 - 3 cos (x)

cos (x) + sin (x) tan (x) = 1

sin (x) - \frac{2}{2} = 0

cot (x) = 0.78

\frac{sin ( 4 0 ^{\circ} )}{8 in} = \frac{sin ( θ )}{3 in}

What is the general solution for 12sin(A)+4=4sin(A)+4 ?
The general solution for 12sin(A)+4=4sin(A)+4 is A=2pin,A=pi+2pin